Problems Description
<p class="p0"> 用函数编程判断一items数是否是回文数,在主函数中调用该函数,如果是回文数,输出<span>1</span><span>,否则输出</span><span>0</span><span>。</span> </p> <p class="p0"> <span> </span> </p> <p class="p0"> 回文数是一种数字,如:<span>9876789</span><span>,这items数字正读是</span><span>9876789</span><span>,倒读也是</span><span>9876789</span><span>,正读倒读一样</span><span>,</span><span>所以这items数字就是回文数。</span> </p> <p class="p0"> <br /> </p>
Input格式
<p class="p0"> 1<span>items数</span><span>n</span><span>。n的位数不能超过10。</span> </p>
Output格式
1或0
Sample
Sample Input 1
9876789
Sample Output 1
1
Submit Code
请先Login后Submit
🤖 AI 解题助手
OpenRouter
就绪