Classic
Clean & simple
Crystal
Glassmorphism + Neon
Cyberpunk
Neon glitch art
🚫
违规Action检测
禁止Use右键菜单
⚠️ 此Action已被系统记录
1

【二维一边推2】字符距离

📝 Solutions 🔵 仅限 C++
Problems Description
<p class="MsoNormal" style="text-indent: 21pt"><span style="font-family: 宋体">设有字符串<span>X</span>,我们称在<span>X</span>的头尾及中间插入任意多items空格后构成的新字符串为<span>X</span>的扩展串,如字符串<span>X</span>为&ldquo;<span class="SpellE"><span>abcbcd</span></span>&rdquo;,则字符串&ldquo;<span class="SpellE"><span>abcb</span></span>□<span class="SpellE"><span>cd</span></span>&rdquo;,&ldquo;□<span>a</span>□<span class="SpellE"><span>bcbcd</span></span>□&rdquo;和&ldquo;<span class="SpellE"><span>abcb</span></span>□<span class="SpellE"><span>cd</span></span>□&rdquo;都是<span>X</span>的扩展串,这里&ldquo;□&rdquo;代表空格字符。</span></p> <p class="MsoNormal" style="text-indent: 21pt"><span style="font-family: 宋体">如果<span>A1</span>是字符串<span>A</span>的扩展串,<span>B1</span>是字符串<span>B</span>的扩展串,<span>A1</span>与<span>B1</span>具有相同的长度,那么我们定义字符串<span>A1</span>与<span>B1</span>的距离为相应位置上的字符的距离总和,而两items非空格字符的距离定义为它们的<span>ASCII</span>码的差的绝对值,而空格字符与其它任意字符之间的距离为已知的定值<span>K</span>,空格字符与空格字符的距离为<span>O</span>。在字符串<span>A</span>、<span>B</span>的所有扩展串中,必定存在两items等长的扩展串<span>A1</span>、<span>B1</span>,使得<span>A1</span>与<span>B1</span>之间的距离达到最小,我们将这一距离定义为字符串<span>A</span>、<span>B</span>的距离。</span></p> <p class="MsoNormal" style="text-indent: 21pt"><span style="font-family: 宋体">请你写一items程序,求出字符串<span>A</span>、<span>B</span>的距离。</span></p>
Input格式
<p class="MsoNormal" style="text-indent: 21pt"><span style="font-family: 宋体">输入FilePage 一行为字符串<span>A</span>,Page 二行为字符串<span>B</span>,<span>A</span>、<span>B</span>均由小写字母组成且长度均不超过<span>2000</span>,Page 三行为一items整数<span>K</span>,<span>1</span>&le;<span>K</span>&le;<span>100</span>,表示空格与其它字符的距离。</span></p> <p class="MsoNormal" align="left" style="text-align: left; text-indent: 21pt">&nbsp;</p>
Output格式
<p><span style="font-family: 宋体">输出File仅一行包含一items整数,表示要求的字符串<span>A</span>、<span>B</span>的距离。</span></p>
Sample
Sample Input 1
cmc snmn 2
Sample Output 1
10
Submit Code
请先Login后Submit

🤖 AI 解题助手

OpenRouter
就绪
👋 你好!我是 AI 解题助手。
我已阅读了这problems题,可以帮你points析思路、提供Code示例。
🔓 完全Free · 无需消耗 Token